Russell Wilson Makes History With New Seahawks Deal

Russell's previous four-deal with the Seahawks was for just under $90 million.

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Russell Wilson and the Seattle Seahawks have come to an agreement on a four-year extension deal that makes NFL history.

SEATTLE. Let’s get it. @Seahawks #GoHawks pic.twitter.com/xeWnEnUzmR

— Russell Wilson (@DangeRussWilson) April 16, 2019

ESPN's Adam Schefter cited a source in a report Monday morning revealing the $140 million extension deal, which includes a hefty $65 million signing bonus. All told, the new deal keeps Wilson on the Seahawks through 2023 and effectively makes him the highest-paid player in the league. The bonus also sets a new record of its own.

Seahawks, QB Russell Wilson agree to four-year, $140M extension. (via @RapSheet) pic.twitter.com/ubGQfQG5er

— NFL (@NFL) April 16, 2019

Wilson himself confirmed the news in a tweet that didn't go into the contract's specifics.

"Seattle, we got a deal," he said as he laid up with Ciara. "Go 'Hawks, but I'ma see y'all in the morning. Time for y'all to go to bed."

SEATTLE. Let’s get it. @Seahawks #GoHawks pic.twitter.com/xeWnEnUzmR

Wilson, whose four-year 2015 contract was for $87.6 million, had previously set a deadline of April 15. Before the signing, the Seahawks' longtime quarterback was allegedly looking into playing for the Giants. The new deal's no-trade clause—the stipulation that his agent, Mark Rodgers, said clinched the deal—forces New York to continue looking for Eli Manning's heir.

“Russell wanted more than anything to stay in Seattle,” Rodgers told NFL reporter Ian Rapoport. “My job was to make sure of it, while doing the best deal possible. The no-trade clause clinched it. We didn’t want to get to draft night three years from now and have his name in trade rumors. Once they offered that, we knew we would have a deal.”

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