BLOG

Celtics Vs. Lakers: The Wifey Showdown

Well folks, we’re in the heat of the NBA finals, and while all the sports reporters are analyzing why the Celtics are sonning the Lakers and what can be done to even up the series (YAWN), we’d like to delve into more important topics, like which squad pulls the badder chicks.

With the series heading back to L.A, the players’ significant others will be on full display to the Hollywood shutterbugs. And we must admit, the two teams stack up pretty well against each other on the female front. We decided to take a look at the confirmed wives and girlfriends of players like Kobe Bryant, Derek Fischer, Paul Pierce and Kevin Garnett to see who’s really winning off the court. See the wifeys and vote on the winning team after the jump.

Captain Knick: Broomsday

The Knicks feel dirty while getting swept by the Celtics.

It seems like it was just last year that three of the NBA’s marquee franchises were stinking up the joint while planning big off-season fishing trips. Oh wait, it was just last year. Since then, the Boston Celtics, Los Angeles Lakers, and New York Knicks each pulled off big trades that were supposed to turn them around (Boston acquired KG and Ray Allen; L.A. stole Pau Gasol; New York admitted head case Zach Randolph to the asylum). Now the Celtics (65-16) and Lakers (56-25) are the cream of their respective conferences and favored to win the title, possibly in an epic clash between the two. The Knicks (23-58) are fiddling with their poles and feeling fishy.

Last night, the Celtics reserve players gave Ew York a Boston creampie, sweeping their season series with a 99-93 defeat while the stars rested for the playoffs. With a season-ending loss tomorrow night to the Indiana Pacers, the Knicks would tie the franchise’s record for L’s caught for the second time in three seasons. As a Knick fan, I’m Celtic green with envy. And vomit. After the jump, see highlights from the 45-point November blowout that signaled just how different the Knicks and Celtics seasons would be.